BigDecimal 无压力 处理一下字符串就好了~

import java.io.IOException;
import java.util.Scanner;
 
public class Main {
 
	public static void main(String[] args) throws IOException {
		Scanner in = new Scanner(System.in);
		while (in.hasNextBigDecimal()) {
			String str = in.nextBigDecimal().pow(in.nextInt()).toPlainString();
			int point = str.indexOf('.');
			int len = str.length();
			if (point == 1 && str.charAt(0) == '0') {
				str = str.substring(1, len);
				len--;
			}
			int i = len - 1;
			while (i > 0 && str.charAt(i) == '0')
				i--;
			if (i != len - 1)
				str = str.substring(0, i + 1);
			len=str.length();
			if(str.charAt(len-1)=='.'){
				str=str.substring(0,len-1);
				if(str.length()==0)
					str="0";
			}
			System.out.println(str);
		}
	}
}